Bagian arsir = 3/8
r = 28 ÷ 2 = 14 cm
- L. arsir
[tex] \tt = \frac{3}{8} \times \pi {r}^{2} [/tex]
[tex] \tt = \frac{3}{8} \times \frac{22}{7} \times {14}^{2} [/tex]
[tex] \tt = \frac{66}{56} \times 196[/tex]
[tex] \tt = \frac{12.936}{56} [/tex]
= 231 cm²
[tex] \pink{\boxed{\red{\boxed{\purple{\mathfrak{\ast ~ \blue{Celia ~ Claire} ~ \ast}}}}}}[/tex]
SOAL 1
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[tex]Rumus : [/tex]
L ⅜ Lingkaran = ⅜ × π × r²
___________________________________________ L ⅜ Lingkaran = ⅜ × 22/7 × (28 ÷ 2)²
L ⅜ Lingkaran = ⅜ × 22/7 × 14²
L ⅜ Lingkaran = ⅜ × 22/7 × 196
L ⅜ Lingkaran = ⅜ × 616
L ⅜ Lingkaran = 231 cm²
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[tex] {\mathcal\color{purple}{{\pink{\underline{\purple{\underline\bold{\pink{K}\bold\color{violet}{h\bold{\pink{a}\bold\color{violet}{d\bold{\pink{i}\bold\color{violet}{j\bold{\pink{a}\bold\color{violet}{h\bold{\pink{A}\bold\color{violet}{m\bold{\pink{j}\bold\color{violet}{a\bold{\pink{d}\bold\color{violet}{1\bold{\pink{2}}}}}}}}}}}}}}}}}}}}}}[/tex]
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